Pasta: 286ee6c6c96280d2fd19f9b53e101908cfe63311 (2017-11-28)

#include <iostream> #include <cmath> using namespace std; class point { double tab[3]; friend istream & operator >> (istream &, point &); public: point() { for(unsigned i=0; i<3; i++) tab[i]=0; } // x jest referencja do tablicy 3 elementowej point(const double (&x)[3]) { tab[0] = x[0]; tab[1] = x[1]; tab[2] = x[2]; } point(const double &x, const double &y, const double &z) { tab[0] = x; tab[1] = y; tab[2] = z; } const double & operator [] (const unsigned &i) const { if (i>2) { cout << "POZA ZAKRESEM!!!"; } return tab[i]; } const double distance(const point &p) const { return( sqrt( (tab[0]-p[0])*(tab[0]-p[0]) + (tab[1]-p[1])*(tab[1]-p[1]) + (tab[2]-p[2])*(tab[2]-p[2]) )); } // dodawanie jako metoda const point operator + (const point &p) const { return point(tab[0]+p[0], tab[1]+p[1], tab[2]+p[2]); } // mnozenie , te moze byc jako metoda const point operator * (const double &P) { return point(tab[0]*P, tab[1]*P, tab[2]*P); } // porownywanie jako metoda bool operator == (const point &p) { double eps = 1e-10; if(abs(this->distance(point()) - p.distance(point())) < eps) return true; return false; } }; //odejmowanie jako niemetoda const point operator - (const point &l, const point &p) { return point(l[0]-p[0], l[1]-p[1], l[2]-p[2]); } // mnozenie ( z lewej strony elelement nienalezacy do klasy wiec nie moze to byc metoda) const point operator * (const double & L, const point &p) { return point(L*p[0], L*p[1], L*p[2]); } // MUSI BYC TU, BO LEWY ARGUMENT << NIE JEST ELEMENTEM KLASY, NIE TRZEBA ZAPRZYJAZANIAC BO MAMY METODY DOSTEPOWE [] ostream & operator << (ostream &out, const point &p) { out << p[0] << " " << p[1] << " " << p[2]; return out; } // musialem zaprzyjaznic bo na metodach dostepowych [] nie dzialalo. istream & operator >> (istream &in, point &p) { in >> p.tab[0] >> p.tab[1] >> p.tab[2]; return in; } bool operator < (const point &l, const point &p) { if (l.distance(point()) < p.distance(point())) return true; return false; } int main() { double x[2][3] = {{1.0, 1.0, 1.0},{1.0, 2.0, 3.0}}; point p1(x[0]), p2(x[1]); const point p3(0.4, 0.2, 0.1); cout << p1 << ", " << p2 << '\n'; cout << p1.distance(point()) << ", "<< p3.distance(p1) << '\n'; cout << p1 + p2 << ", " << p1 - p3 << '\n'; cout << 3.14 * p2 << ", " << p2 * 3.14 << '\n'; cout << (p1 < p3) << ", " << (p1 == point(1.0000000001, 1.0, 1.0)) << '\n'; cin >> p1; cout << p1 << '\n'; }